document.write( "Question 492615: What quantity of 80 per cent acid solution must be mixed with a 25 percent solution to produce 660 mL of a 50 per cent solution? \n" ); document.write( "
Algebra.Com's Answer #335151 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
percent percentage ---------------- quantity
\n" ); document.write( "Acid I 80 ---------------- x ml
\n" ); document.write( "Acid II 25 ---------------- 660 - x ml
\n" ); document.write( "Mixture 50.00% ---------------- 660
\n" ); document.write( "
\n" ); document.write( "80 x + 25 ( 660 - x ) = 50 * 660
\n" ); document.write( "
\n" ); document.write( "80 x + 16500 - 25 x = 33000
\n" ); document.write( "80 x - 25 x = 33000 - 16500
\n" ); document.write( "55 x = 16500
\n" ); document.write( "/ 55
\n" ); document.write( " x= 300 ml 80.00% Acid I
\n" ); document.write( " 360 ml 25.00% Acid II
\n" ); document.write( "
\n" ); document.write( "
\n" );