document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=492648>Question 492648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help us. My daughter and I just cannot figure this out. \r<BR>\n" );
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document.write( "Dean has a small garden with a perimeter of 20 ft. and an area of 25 square ft. He wants to triple the dimensions of his garden next year. what will the new perimeter and new area of his larger garden be? explain the changes in perimeter and area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335113 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335113\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> perimeter of present garden = 20 ft. Area = 25 sq.ft<BR>\n" );
document.write( "2(l+w)=20<BR>\n" );
document.write( "l+w=10\r<BR>\n" );
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document.write( "l*w = 25<BR>\n" );
document.write( "l=25/w\r<BR>\n" );
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document.write( "substitute l in first equation<BR>\n" );
document.write( "25/w+ w= 10\r<BR>\n" );
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document.write( "LCD = w<BR>\n" );
document.write( "multiply by w\r<BR>\n" );
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document.write( "25*w /w +w^2=10w\r<BR>\n" );
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document.write( "w^2-10w+25w=0\r<BR>\n" );
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document.write( "(w-5)^2=0<BR>\n" );
document.write( "w= +/-5<BR>\n" );
document.write( "so w=5 <BR>\n" );
document.write( "so it is a square.\r<BR>\n" );
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document.write( "increase size three times<BR>\n" );
document.write( "length & width = 15 ft<BR>\n" );
document.write( "perimeter = 60 ft<BR>\n" );
document.write( "area = 15*15 = 225 sq.ft\r<BR>\n" );
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document.write( " </SPAN>\n" );
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