document.write( "Question 492498: a square and a rectangle have the same area. the length of the rectangle is 8 more than s side of the square, and the width of the rectangle is 4 less than a side of the square. find a side of the square. \n" ); document.write( "

Algebra.Com's Answer #335090 by WhuddaPeach(6) $\"\"$ $\"About$

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Basically, this tells us that
\n" ); document.write( " $\"s%2As+=+%28s%2B8%29%28s-4%29\"$
\n" ); document.write( "s is the length of the square's side. So, the area of the square is s^2, and the area of the rectangle is (s+8)(s-4)
\n" ); document.write( "Simplify.
\n" ); document.write( " $\"s%5E2+=+s%5E2%2B4s-32\"$
\n" ); document.write( "The s^2 cancel out.
\n" ); document.write( " $\"0+=+4s-32\"$
\n" ); document.write( "Add 32 to both sides.
\n" ); document.write( " $\"32+=+4s\"$
\n" ); document.write( "Divide by 4.
\n" ); document.write( " $\"8+=+s\"$
\n" ); document.write( " \n" ); document.write( "

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