document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=50462>Question 50462</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation. it is completing the square:\r<BR>\n" );
document.write( "\n" );
document.write( "2b2 + 7b + 4=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33507 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33507\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2b^2 + 7b + 4=0<BR>\n" );
document.write( "2(b^2+(7/2)b+? = -4<BR>\n" );
document.write( "b^2+(7/2)b+(7/4)^2=-2+(7/4)^2<BR>\n" );
document.write( "(b+(7/4))^2 = -32/16 + 49/16<BR>\n" );
document.write( "(b+(7/4))^2 = 17/16<BR>\n" );
document.write( "Take the sqrt of both sides to get:<BR>\n" );
document.write( "b+7/4= (sqrt17)/4 or b+7/4 = -(sqrt17)/4<BR>\n" );
document.write( "b = [-7+(sqrt17)]/4 or  b = [-7-(sqrt17)]/4\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "stan H.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );