document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=492497>Question 492497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the lengths of the sides of a triangle whose perimeter is 37. The measure of the first side of the triangle is 8 less than the second side, and the secoond side is twice the length of the third.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335061 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335061\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = 2x - 8<BR>\n" );
document.write( "B = 2x<BR>\n" );
document.write( "C = x<BR>\n" );
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document.write( "2x - 8 + 2x + x = 37<BR>\n" );
document.write( "5x = 45<BR>\n" );
document.write( "x = 9<BR>\n" );
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document.write( "A = 18 - 8 = 10<BR>\n" );
document.write( "B = 18<BR>\n" );
document.write( "C = 9<BR>\n" );
document.write( "10 + 18 + 9 = 37<BR>\n" );
document.write( "This does check.<BR>\n" );
document.write( "cleomenius<BR>\n" );
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