document.write( "Question 491814: i am a 3 digit number divisible by 3.my tens digit is 3 times as great as my hundreds digit and the sum of my digits is 15. if you reverse my digits i am divisible by 6 and 3...... what number am i? \n" ); document.write( "
Algebra.Com's Answer #335024 by ankor@dixie-net.com(22740)\"\" \"About 
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i am a 3 digit number divisible by 3.
\n" ); document.write( "100a + 10b + c
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\n" ); document.write( "my tens digit is 3 times as great as my hundreds digit
\n" ); document.write( "b = 3a, from this we know a = 1, 2, 3, then b = 3, 6, 9
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\n" ); document.write( "and the sum of my digits is 15.
\n" ); document.write( "a + b + c = 15
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\n" ); document.write( "if you reverse my digits i am divisible by 6 and 3
\n" ); document.write( "100c + 10b + a
\n" ); document.write( ":
\n" ); document.write( "this is a logic problem, an equation won't help us here
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\n" ); document.write( "From the given information b = 3a, and the sum of the 3 digits = 15, we have:
\n" ); document.write( "1 3 ___; three single digits can't add up to 15
\n" ); document.write( "2 6 _7_; this has to be the number
\n" ); document.write( "3 9 _3_; reverse number is not different
\n" ); document.write( ":
\n" ); document.write( "Check for division by 3 and 6
\n" ); document.write( "267/3 = 89
\n" ); document.write( "762/6 = 127
\n" ); document.write( ":
\n" ); document.write( "267 is the number\r
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