document.write( "Question 492128: QS bisects ∠PQR, m∠PQR = (4x + 2) °, and
\n" ); document.write( "m∠SQR = (3x - 6) °. What is the value of x? \n" ); document.write( "
Algebra.Com's Answer #335007 by cleomenius(959)\"\" \"About 
You can put this solution on YOUR website!
Since QS bisects angle PQR, SQR is 1/2 of PQR.
\n" ); document.write( "2(3x - 6) = (4x + 2)
\n" ); document.write( "6x -12 = 4x + 2
\n" ); document.write( "2x = 14.
\n" ); document.write( "x = 7
\n" ); document.write( "SQR = (7)(3) - 6 = 15
\n" ); document.write( "PQR = 4(7) + 2 = 30
\n" ); document.write( "This does check.
\n" ); document.write( "cleomenius.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );