document.write( "Question 50223: A sum of $10000 is split, and the two parts are invested at 5% and 6% respectively. if the interest from the 5% investment exceeds the interest from the 6% investment by $60, how much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #33500 by pigpen(1)\"\" \"About 
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.05(10000-x)=.06x+60\r
\n" ); document.write( "\n" ); document.write( "500-.05x = .06x+60
\n" ); document.write( " +.05x +.05x\r
\n" ); document.write( "\n" ); document.write( "500 = .11x+60
\n" ); document.write( "-60 -60\r
\n" ); document.write( "\n" ); document.write( "440 = .11x
\n" ); document.write( "--- ----
\n" ); document.write( ".11 .11\r
\n" ); document.write( "\n" ); document.write( "4000 = x\r
\n" ); document.write( "\n" ); document.write( "$4000 @ 5%
\n" ); document.write( "10000 - x = 6% so 10000-4000 = $6000 @6%\r
\n" ); document.write( "\n" ); document.write( "pigpen
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