document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37669>Question 37669</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0201812487/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Six apples and three oranges cost $1.77. Two apples and five oranges cost $1.27. Find the cost of each apple and the cost of an orange. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33499 by </B><A HREF=/tutors/aboutme.mpl?userid=jackytavares><B>jackytavares(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jackytavares><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jackytavares><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33499\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> apples = x and oranges = y\r<BR>\n" );
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document.write( "The point for this is to see how much oranges and apples cost. [each] \r<BR>\n" );
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document.write( "original equation: \r<BR>\n" );
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document.write( "6x+3y=1.77 <BR>\n" );
document.write( "2x+5y=1.27\r<BR>\n" );
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document.write( "(~second equation~ multiply (3) to everything [2x,5y and 1.27]) just like showed below:\r<BR>\n" );
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document.write( "(3)2x+(3)5y=(3)1.27 \r<BR>\n" );
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document.write( "because we are trying to get the same beggining number with the same variable [6x] which would give you: \r<BR>\n" );
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document.write( "6x+15y=3.81 [yay! we got [6x] for the second equation like we planned]\r<BR>\n" );
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document.write( "now put the 1st equation that we didn't change (6x+3y=1.77) down below the one we change. <BR>\n" );
document.write( "It would look like this:\r<BR>\n" );
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document.write( "6x+15y=3.81<BR>\n" );
document.write( "6x+3y=1.77 [this was the one we didn't changed]\r<BR>\n" );
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document.write( "cross out the two 6x [from the first and second equation] and subtract 3.81 and 1.77 \r<BR>\n" );
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document.write( "you would be left with:\r<BR>\n" );
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document.write( "15y-3y=2.04\r<BR>\n" );
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document.write( "subtract the 15y and 3y........\r<BR>\n" );
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document.write( "12y=2.04\r<BR>\n" );
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document.write( "divide 12 to each side.....\r<BR>\n" );
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document.write( "y=.17 [so now we know oranges are $.17]\r<BR>\n" );
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document.write( "Now we have to find out how much do apples cost.\r<BR>\n" );
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document.write( "Now we go way way way back. our original equations\r<BR>\n" );
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document.write( "remember...........\r<BR>\n" );
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document.write( "6x+3y=1.77<BR>\n" );
document.write( "2x+5y=1.27\r<BR>\n" );
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document.write( "now that we know how much oranges cost \r<BR>\n" );
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document.write( "substute the cost [y=.17] to the original equation [it doesn't matter which one but it has to be only ONE] \r<BR>\n" );
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document.write( "lets do the first one....yea?\r<BR>\n" );
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document.write( "you have to replace it where the \"y\" is at. just as shown below.....\r<BR>\n" );
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document.write( "[first equation] ->6x+3(.17)=1.77 [replace .17 with the variable [y]\r<BR>\n" );
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document.write( "6x+.51=1.77\r<BR>\n" );
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document.write( "now subtract 1.77 and .51\r<BR>\n" );
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document.write( "so you will get:\r<BR>\n" );
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document.write( "6x=1.26\r<BR>\n" );
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document.write( "divide [6] to each side......<BR>\n" );
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document.write( "your answer x=.21\r<BR>\n" );
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document.write( "now you know oranges are $.17<BR>\n" );
document.write( "and apples are $.21\r<BR>\n" );
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document.write( "hope you enjoyed it and learned.<BR>\n" );
document.write( "thanx for your attention if u have questions about it cantact me at \r<BR>\n" );
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document.write( "tavares261@msn.com    \r<BR>\n" );
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document.write( "ask for Jacky Tavares<BR>\n" );
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