document.write( "Question 492142: Please help me solve this equation: log16x + log8 + log2x = 19/12 \n" ); document.write( "
Algebra.Com's Answer #334963 by lwsshak3(11628)\"\" \"About 
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log16x + log8 + log2x = 19/12
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\n" ); document.write( "log16x + log8 + log2x = 19/12
\n" ); document.write( "place under a single log
\n" ); document.write( "log[16x*8*2x]=19/12
\n" ); document.write( "convert to exponential form: base(10) raised to log of number(19/12)=number[16x*8*2x]
\n" ); document.write( "10^(19/12)=16x*8*2x=256x^2
\n" ); document.write( "10^(19/12)=256x^2
\n" ); document.write( "x^2=256/10^(19/12)=38.3119/256=.1497
\n" ); document.write( "x=±√.1497
\n" ); document.write( "x=.3869
\n" ); document.write( " or
\n" ); document.write( "x=-.3869 (reject, x>0)
\n" ); document.write( "Check:
\n" ); document.write( "log(16*.3869)+log(8)+log(2*.3869)=1.5834
\n" ); document.write( "19/12=1.5833 \n" ); document.write( "
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