document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=492108>Question 492108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi can someone please help me with this?\r<BR>\n" );
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document.write( "Use the “difference of squares” rule to factor the following expression:\r<BR>\n" );
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document.write( "16x^4-121y^4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334948 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i believe the answer would be:\r<BR>\n" );
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document.write( "(4x^2 - 11y^2) * (4x^2 + 11y^2)\r<BR>\n" );
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document.write( "you will get:\r<BR>\n" );
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document.write( "16x^4 - 4x^2*11y^2 + 4x^2*11y^2 - 121y^4\r<BR>\n" );
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document.write( "the middle terms will cancel out and you will be left with:\r<BR>\n" );
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document.write( "16x^4 - 121y^4\r<BR>\n" );
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document.write( "this is the same as (a^2 - b^2) = (a-b) * (a+b)\r<BR>\n" );
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document.write( "you get a^2 - ab + ab - b^2 which results in a^2 - b^2 because the middle terms cancel out.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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