document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=50390>Question 50390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Any help with the below question will be greatly appreciated.  I can't seem to figure it out...\r<BR>\n" );
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document.write( "A bacteria culture started with a count of 480 at 8:00 A.M. and after t hours is expected to grow to f(t)=480(3/2)^t.  Estimate the number of bacteria in the culture at noon the same day.  \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33494 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33494\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  bacteria culture started with a count of 480 at 8:00 A.M. and after t hours is expected to grow to f(t)=480(3/2)^t. Estimate the number of bacteria in the culture at noon the same day.<BR>\n" );
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document.write( "From 8AM to noon is 4 hours, so t=4.<BR>\n" );
document.write( "f(4)=480(3/2)^4<BR>\n" );
document.write( "f(4)=480(5.0625)<BR>\n" );
document.write( "f(4)= 2430 bacteria.\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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