document.write( "Question 492089: The sum of the present ages of Ian and his Brother is 45, In 5years, Ian's age will be five-sixths of his brothers age. Findtheir present ages.
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document.write( "I know the answers but can't figure out how to GET the answers! THANKS \n" );
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Algebra.Com's Answer #334934 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "x=Current age of Ian \n" ); document.write( "y=Current age of Brother\r \n" ); document.write( "\n" ); document.write( "x+y=45 \n" ); document.write( "x=45-y.........(1) \n" ); document.write( "In five years means we have to add 5 years in both ages, then Ian age will be five-sixths of his brother\r \n" ); document.write( "\n" ); document.write( "x+5=(y+5)(5/6) \n" ); document.write( "Multiply by 6 both sides \n" ); document.write( "6(x+5)=(y+5)(5) \n" ); document.write( "6x+30=5y+25 \n" ); document.write( "6x=5y+25-30 \n" ); document.write( "6x=5y-5.........(2) \n" ); document.write( "Put the value of x from (1) to (2) \n" ); document.write( "6(45-y)=5y-5 \n" ); document.write( "270-6y=5y-5 \n" ); document.write( "270+5=5y+6y \n" ); document.write( "275=11y \n" ); document.write( "y=275/11 \n" ); document.write( "y=25 \n" ); document.write( "Put the value of y in (1) \n" ); document.write( "x=45-y.........(1) \n" ); document.write( "x=45-25 \n" ); document.write( "x=20\r \n" ); document.write( "\n" ); document.write( "Ian is 20 and his brother is 25 years old\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |