document.write( "Question 492037: can you please help me answer the problem \"+sqrt%28x%2B5%29-6=-2+\"? thank you! \n" ); document.write( "
Algebra.Com's Answer #334904 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"+sqrt%28x%2B5%29-6=-2+\"\r
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\n" ); document.write( "\n" ); document.write( "add 6 to both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "\"+sqrt%28x%2B5%29+=+-2+%2B+6\"\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get:\r
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\n" ); document.write( "\n" ); document.write( "\"+sqrt%28x%2B5%29+=+4\"\r
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\n" ); document.write( "\n" ); document.write( "square both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x+%2B+5%29+=+16\"\r
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\n" ); document.write( "\n" ); document.write( "subtract 5 from both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+11\"\r
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\n" ); document.write( "\n" ); document.write( "that's your answer.\r
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\n" ); document.write( "\n" ); document.write( "substitute 11 for x in the original equation to get:\r
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\n" ); document.write( "\n" ); document.write( "\"+sqrt%28x%2B5%29-6=-2+\" becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"+sqrt%2811%2B5%29-6=-2+\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"+sqrt%2816%29-6=-2+\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"4+-+6+=+-2\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"-2+=+-2\" which is true, confirming the value of 11 for x is good.\r
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