document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=492021>Question 492021</A>: <I><SPAN STYLE=\"word-break: break-all;\"> at what rate dose a skier travel if he has gone 10 miles in 40 minutes. If a less experienced skier travels the same distance in twice the time what is their rate. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334901 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 10 mi/40 minuts = 1/4 mile per minute<BR>\n" );
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document.write( "twice the time --> 1/8 mile/min<BR>\n" );
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