document.write( "Question 491981: Find its area.
\n" ); document.write( "A = (-2, 5); B = (1, 3); C = (-1, 0)
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Algebra.Com's Answer #334878 by cleomenius(959)\"\" \"About 
You can put this solution on YOUR website!
We will use the distance formula to find the distance between vertices.
\n" ); document.write( "\"sqrt%28%28x2+-+x1%29%5E2+%2B+%28y2+-+y1%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "AB = \"sqrt%28%281+-+-2+%29%5E2+%2B+%283+-+5%29%5E2%29\"
\n" ); document.write( "AB = \"sqrt%28%283%29%5E2+%2B+%282%29%5E2%29\"
\n" ); document.write( "AB = \"sqrt%2813%29\"
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\n" ); document.write( "BC = \"sqrt%28%28-1+-+-1%29%5E2+%2B+%280+-+3%29%5E2%29\"
\n" ); document.write( "BC = \"sqrt%28%282%29%5E2+%2B+%283%29%5E2%29\"
\n" ); document.write( "BC = \"sqrt%2813%29\"
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\n" ); document.write( "AC = \"sqrt%28%28-1+-+-2%29%5E2+%2B+%280+-+5%29%5E2%29\"
\n" ); document.write( "AC = \"sqrt%28%281%29%5E2+%2B+%285%29%5E2%29\"
\n" ); document.write( "AC = \"sqrt%2826%29\"
\n" ); document.write( "Ac = \"sqrt%282%29\"\"sqrt%2813%29\"
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\n" ); document.write( "At this point, I converted to decimals, they are easier to work with.
\n" ); document.write( "AC = 3.6
\n" ); document.write( "BC = 3.6
\n" ); document.write( "AC = 5.1
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\n" ); document.write( "Now, we use Herons formula to find the area.
\n" ); document.write( "Area = \"sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29\"
\n" ); document.write( "s = (3.6 + 3.6 + 5.1) / 2
\n" ); document.write( "s = 12.3/ 2 =6.15
\n" ); document.write( "Area = \"sqrt%286.15%29%282.55%29%282.55%29%281.05%29%29\"
\n" ); document.write( "Area = \"sqrt%2819.28%29\"
\n" ); document.write( "Area = 4.4
\n" ); document.write( "Cleomenius.
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