document.write( "Question 491644: Bob's dad is 27 years older than Bob. The sum of their ages 5 years ago was 45 years. How old is Bob now? \n" ); document.write( "
Algebra.Com's Answer #334858 by Maths68(1474)\"\" \"About 
You can put this solution on YOUR website!
Let
\n" ); document.write( "d=Current age of dad
\n" ); document.write( "b=Current age of Bob\r
\n" ); document.write( "\n" ); document.write( "Bob's dad is 27 years older than Bob so if we add 27 years to the Bob’s age both will be of same age\r
\n" ); document.write( "\n" ); document.write( "d=b+27………(1)\r
\n" ); document.write( "\n" ); document.write( "5 years ago means subtract 5 from both the ages
\n" ); document.write( "Dad age 5 years ago = d-5
\n" ); document.write( "Bob age 5 years ago = b-5\r
\n" ); document.write( "\n" ); document.write( "The sum of their ages 5 years ago was 45 years means
\n" ); document.write( "(d-5)+(b-5)=45
\n" ); document.write( "d-5+b-5=45
\n" ); document.write( "d+b-10=45
\n" ); document.write( "d+b=45+10
\n" ); document.write( "d+b=55
\n" ); document.write( "b=55-d…………………(2)\r
\n" ); document.write( "\n" ); document.write( "Put the value of b in (1), we have
\n" ); document.write( "d=b+27………(1)
\n" ); document.write( "d=55-d+27
\n" ); document.write( "d+d=55+27
\n" ); document.write( "2d=82
\n" ); document.write( "Divide by 2 both sides
\n" ); document.write( "2d/2=82/2
\n" ); document.write( "d=41\r
\n" ); document.write( "\n" ); document.write( "put the value of d in (2), we have\r
\n" ); document.write( "\n" ); document.write( "b=55-d…………………(2)
\n" ); document.write( "b=55-41
\n" ); document.write( "b=14\r
\n" ); document.write( "\n" ); document.write( "Bob is 14 and Daddy is 41 years old
\n" ); document.write( " \n" ); document.write( "
\n" );