document.write( "Question 491879: Jenny drove to her cabin on the lake and back. It took 0.6 hours longer to get there than it did to get back. The average speed of the trip was 46 km/h. The average speed of the trip back was 52 km/h. How many hours did the trip there take? \n" ); document.write( "
Algebra.Com's Answer #334856 by lwsshak3(11628)\"\" \"About 
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Jenny drove to her cabin on the lake and back. It took 0.6 hours longer to get there than it did to get back. The average speed of the trip was 46 km/h. The average speed of the trip back was 52 km/h. How many hours did the trip there take?
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\n" ); document.write( "let x=distance to cabin
\n" ); document.write( "travel time =distance/speed
\n" ); document.write( "x/46-x/52=0.6
\n" ); document.write( "LCD: 46*52
\n" ); document.write( "52x-46x=0.6*46*52
\n" ); document.write( "6x=1435.20
\n" ); document.write( "x=1435.20/6=239.2 km
\n" ); document.write( "Travel time to cabin=x/46=239.2/46=5.2 hrs
\n" ); document.write( "Travel time back=x/52=239.2/52=4.6 hrs
\n" ); document.write( "Difference=5.2-4.6=0.6 hrs
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