document.write( "Question 491893: craig is 5 years older than bruce. the product of their ages is 1184. how old are they? i know their ages are 32 and 37 but how do i set it up? \n" ); document.write( "
Algebra.Com's Answer #334848 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "c=Current age of Craig \n" ); document.write( "b=Current age of Bruce\r \n" ); document.write( "\n" ); document.write( "If we add 5 years to the Bruce age then both will be of same age \n" ); document.write( "c=b+5…….(1) \n" ); document.write( "the product of their ages is 1184 \n" ); document.write( "c*b=1184 \n" ); document.write( "Divide above equation by ‘c’ both sides \n" ); document.write( "cb/c=1184/c \n" ); document.write( "b=1184/c……….(2)\r \n" ); document.write( "\n" ); document.write( "Put the value of b in (1) we have\r \n" ); document.write( "\n" ); document.write( "c=(1184/c)+5 \n" ); document.write( "Multiply by ‘c’ both sides \n" ); document.write( "c^2=1184+5c \n" ); document.write( "Now solve for ‘c’ \n" ); document.write( "c^2-5c-1184=0 \n" ); document.write( "c^2-37c+32c-1184=0 \n" ); document.write( "c(c-37)+32(c-37)=0 \n" ); document.write( "(c-37)(c+32)=0 \n" ); document.write( "c-37=0 or c+32=O \n" ); document.write( "c=37 or c=-32 (which is impossible - Craig will not born after 32 years from now) \n" ); document.write( " Therefore C=37 so Craig is 37 years old\r \n" ); document.write( "\n" ); document.write( "Put the value of ‘c’ in equation (1) we have \n" ); document.write( "c=b+5 \n" ); document.write( "37=b+5 \n" ); document.write( "37-5=b \n" ); document.write( "b=32\r \n" ); document.write( "\n" ); document.write( "So Bruce is 32 years old. \n" ); document.write( " \n" ); document.write( " |