document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=491922>Question 491922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the value of base is (x+16) inches and the height is (x+9) inches. the area of the triangle is 130 inches. then what is the value of x in the base and in the height?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334841 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334841\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of triangle = 1/2 * base*height\r<BR>\n" );
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document.write( "Area = 1/2 * (x+16)(x+9)\r<BR>\n" );
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document.write( "130= 1/2 * x^2+25x+144\r<BR>\n" );
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document.write( "multiply by 2<BR>\n" );
document.write( "260= x^2+25x+144<BR>\n" );
document.write( "x^2+25x-116=0\r<BR>\n" );
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document.write( "x^2+29x-4x-116=0\r<BR>\n" );
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document.write( "x(x+29)_4(x+29)=0<BR>\n" );
document.write( "(x-4)(x+29)=0<BR>\n" );
document.write( "x= 4 OR -29.<BR>\n" );
document.write( "Ignore negative value.<BR>\n" );
document.write( "x= 4\r<BR>\n" );
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