document.write( "Question 491888: f(x)=25xsquare2+20x+4 find the y intercepts and x intercepts \n" ); document.write( "
Algebra.Com's Answer #334827 by ccs2011(207)\"\" \"About 
You can put this solution on YOUR website!
Intercepts can be found by plugging in zero for the other variable since anywhere on y-axis, x=0 and anywhere on x-axis, y=0
\n" ); document.write( "Y-intercept: set x=0
\n" ); document.write( "--> y = 0+0+4 = 4
\n" ); document.write( "Y-intercept is the point (0,4), this is where the graph crosses the y-axis
\n" ); document.write( "X-intercept: set y=0
\n" ); document.write( "--> 25x^2 +20x +4 = 0
\n" ); document.write( "I will use the quadratic solver to show how to find x:\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"25x%5E2%2B20x%2B4+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2820%29%5E2-4%2A25%2A4=0\".
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\n" ); document.write( " Discriminant d=0 is zero! That means that there is only one solution: \"x+=+%28-%2820%29%29%2F2%5C25\".
\n" ); document.write( " Expression can be factored: \"25x%5E2%2B20x%2B4+=+25%28x--0.4%29%2A%28x--0.4%29\"
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\n" ); document.write( " Again, the answer is: -0.4, -0.4.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+25%2Ax%5E2%2B20%2Ax%2B4+%29\"
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