document.write( "Question 490774: Four times the smaller of two consecutive odd integers is the same as 73 less than 5 times the larger. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #334825 by Maths68(1474)\"\" \"About 
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Let x+1 is smaller odd integer
\n" ); document.write( "and x+3 is larger odd integer
\n" ); document.write( "4 times of the smaller integer = 4(x+1)
\n" ); document.write( "5time of the larger integer=5(x+3)\r
\n" ); document.write( "\n" ); document.write( "Condition says
\n" ); document.write( "4(x+1)=73-5(x+3)
\n" ); document.write( "4x+4=73-5x-15
\n" ); document.write( "4x+5x=73-15-4
\n" ); document.write( "9x=54
\n" ); document.write( "Divide by 9 both sides
\n" ); document.write( "9x/9=54/9
\n" ); document.write( "x=6\r
\n" ); document.write( "\n" ); document.write( "Smaller odd integer = x+1
\n" ); document.write( " = 6+1
\n" ); document.write( " = 7
\n" ); document.write( "Larger odd integer = x+3
\n" ); document.write( " =6+3
\n" ); document.write( " =9
\n" ); document.write( " \n" ); document.write( "
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