document.write( "Question 491864: a person invests a total of $23500 in two accounts. one investment earned 8% annual simple interest while the other earned 5.5% annual interest. the amount of interest earned for one year was &=$1680. how much was invested in each account? \n" ); document.write( "

Algebra.Com's Answer #334794 by mananth(16946) $\"\"$ $\"About$

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Investment I 8.00% per annum ---x
\n" ); document.write( "Investment II 5.50% per annum ---y
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\n" ); document.write( "x + y= 23500 ------------------------1
\n" ); document.write( "8.00% x + 5.50% y = $1,680.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "8 x + 5.5 y = $168,000.00 --------2
\n" ); document.write( "
\n" ); document.write( "Multiply (1) by -8
\n" ); document.write( "we get
\n" ); document.write( "
\n" ); document.write( "-8 x -8 y = -188000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "0 x -2.5 y = -$20,000.00
\n" ); document.write( "
\n" ); document.write( "divide by -2.5
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\n" ); document.write( " y = $8,000.00 investment at
\n" ); document.write( "Balance $15,500.00 investment at
\n" ); document.write( "CHECK
\n" ); document.write( "$15,500.00 $1,240.00
\n" ); document.write( "$8,000.00 $440.00
\n" ); document.write( "Total $1,680.00
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