document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=491876>Question 491876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help\r<BR>\n" );
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document.write( "A tank holds 30 liters of a chemical solution. Currently, the solution has a strength of 60%. How much of this should be drained and replaced with a 90% solution to get a final strength of 80%?\r<BR>\n" );
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document.write( "How many liters should be drained and replaced with 90 % solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334791 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A tank holds 30 liters of a chemical solution. Currently, the solution has a strength of 60%. How much of this should be drained and replaced with a 90% solution to get a final strength of 80%? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "active - active + active = active<BR>\n" );
document.write( "0.60*30 - 0.60x + 0.90x = 0.80*30<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "60*30  - 60x + 90x = 80*30<BR>\n" );
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document.write( "30x = 20*30<BR>\n" );
document.write( "x = 20 liters (amt of 60% to be replaced by 90% solution)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H. </SPAN>\n" );
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