document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=491489>Question 491489</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If each engineer needs to meet with each other individually, how many engineers would equal 66 meetings? I cannot come up with this number in my son's homework question.  I get 8 engineers at 56 meetings, or 9 engineers at 72 meetings. Please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334730 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We want nC2 = 66 because the number of ways to choose two engineers to meet out of a pool of n is 66. Hence,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \frac{n!}{(n-2)!2!} = 66\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \frac{n!}{(n-2)!} = 132\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE n(n-1) = 132\">\r<BR>\n" );
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document.write( "n = 12 engineers </SPAN>\n" );
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