document.write( "Question 491645: Two trains heading toward each other are 360 miles apart. One train travels at 10 mi/hr faster than the other train. If they meet in four hours how fast is each train traveling? \n" ); document.write( "
Algebra.Com's Answer #334716 by Edwin McCravy(20059)\"\" \"About 
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Two trains heading toward each other are 360 miles apart. One train travels at 10 mi/hr faster than the other train. If they meet in four hours how fast is each train traveling?
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document.write( "Make this chart:\r\n" );
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document.write( "              Distance   Rate  Time\r\n" );
document.write( "Slower train\r\n" );
document.write( "Faster train\r\n" );
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document.write( "Let the slower train's rate be x.  Then the faster train's rate is x+10.\r\n" );
document.write( "Fill this in and the time for each is 4 hours, so fill that in too:\r\n" );
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document.write( "              Distance   Rate  Time\r\n" );
document.write( "Slower train              x      4  \r\n" );
document.write( "Faster train             x+10    4\r\n" );
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document.write( "Use distance = rate·time to fill in the distances:\r\n" );
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document.write( "              Distance    Rate  Time\r\n" );
document.write( "Slower train     4x        x      4  \r\n" );
document.write( "Faster train   4(x+10)    x+10    4\r\n" );
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document.write( "The distance must total the 360 miles they were initially apart, so\r\n" );
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document.write( "   4x + 4(x+10) = 360 \r\n" );
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document.write( "Solve and get x = 40 mph \r\n" );
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document.write( "So the slower train was going x=40 mph and the faster train was\r\n" );
document.write( "going x+10 = 40+10 or 50 mph.\r\n" );
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document.write( "In 4 hours the slower train went 160 miles and the faster train went\r\n" );
document.write( "200 miles and their total distance in opposite directions toward the\r\n" );
document.write( "point at which they met is the total 160+200=360 miles they were apart originally.  So it checks.\r\n" );
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document.write( "Edwin
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