document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=491314>Question 491314</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the length of the hypotenuse when the area of a isosceles right triangle is 200 cm.sq. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334710 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area is 1/2 base * height<BR>\n" );
document.write( "400 = b*h, since they the same measure the legs are 20 cm.<BR>\n" );
document.write( "Now, we can use the Pythagorean theorem, 20^2 + 20^2 = c^2.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28800%29 ALIGN=MIDDLE  ALT=\"sqrt%28800%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = hypotenuse.<BR>\n" );
document.write( "28.28 cm would be the hypotenuse, with the legs 20 cm each.<BR>\n" );
document.write( "Cleomenius.<BR>\n" );
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