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How do you find the height of triangle whose base is 44cm and sides Are 38cm and 30cm?
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\n" ); document.write( "Draw a triangle with the apex labeled, A, the angle on the left, B and the the angle on the right, C. Draw a line from the apex down to where it intersects the base BC. Call this line h=height and label the point of intersection as D. The base is divided into two parts. Call the left part x, and the right part (44-x). We now have two right triangles to work with, ACD and ABD, and sides AB=38, AC=30, BC=44.
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\n" ); document.write( "Using Pythagorean Theorem:
\n" ); document.write( "AB^2-h^2=x^2
\n" ); document.write( "38^2-h^2=x^2
\n" ); document.write( "h^2=38^2-x^2
\n" ); document.write( "..
\n" ); document.write( "AC^2-h^2=(44-x)^2
\n" ); document.write( "30^2-h^2=44^2-88x+x^2
\n" ); document.write( "sub h^2
\n" ); document.write( "30^2-38^2+x^2=44^2-88x+x^2
\n" ); document.write( "900-1444=1936-88x
\n" ); document.write( "-2480=-88x
\n" ); document.write( "x=2480/88=28.18
\n" ); document.write( "..
\n" ); document.write( "h^2=38^2-x^2=1444-28.18^2=649.79
\n" ); document.write( "h=√649.79=25.49 cm
\n" ); document.write( "ans:
\n" ); document.write( "Height of triangle=25.49 cm \n" ); document.write( "