document.write( "Question 491560: A company is planning to introduce a new product. The company estimates that $500 worth of
\n" );
document.write( "new equipment will be needed to manufacture this new type of product and that it will cost $15
\n" );
document.write( "per item to manufacture. The company also estimates that the revenue from each item will be $31.
\n" );
document.write( "Find the number of items that the company needs to produce and sell in order to break-even.\r
\n" );
document.write( "\n" );
document.write( "i just need to know how to set the problem up.
\n" );
document.write( "i had 500=15x+y
\n" );
document.write( "but after that i realized that im wrong. \n" );
document.write( "
Algebra.Com's Answer #334689 by cleomenius(959)![]() ![]() You can put this solution on YOUR website! 500 + 15x = 31x; This is how you set it up. \n" ); document.write( "* \n" ); document.write( "***Keep in mind the number of variables; in this problem we just need one, x, for the number of items.*** \n" ); document.write( "* \n" ); document.write( "500 = 16x \n" ); document.write( "31.25 = x \n" ); document.write( "You will need 32 to break even/ show a profit. \n" ); document.write( "15(31.25) = 468.75 + 500 = 968.75 \n" ); document.write( "31.25(31) = 968.75 \n" ); document.write( "Cleomenius. \n" ); document.write( " \n" ); document.write( " |