document.write( "Question 50350: find the equation of the line containing (-3,1)and perpendicular to the line 2x+3y=5
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Algebra.Com's Answer #33460 by tutorcecilia(2152)\"\" \"About 
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The slopes of perpendicular lines are are negative reciprocals of each other.
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\n" ); document.write( "Line #1:
\n" ); document.write( "2x+3y=5 [Re-write in the slope-intercept form by solving for \"y\"]
\n" ); document.write( "y=-2/3x+5/3 [The slope (m) = -2/3]
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\n" ); document.write( "Line 2 has points (-3,1). The slope is the negative reciprocal of (-2/3) = (-(-3/2) = 3/2
\n" ); document.write( "y=mx+b [Plug in the pionts and slope for Line 2]
\n" ); document.write( "1=(3/2)(-3)+b [Solve for b]
\n" ); document.write( "1=-9/2+b
\n" ); document.write( "1+9/2=-9/2 - 9/2+b
\n" ); document.write( "18/2=b
\n" ); document.write( "9=b
\n" ); document.write( "y=3/2x+9 [The equation of Line #2 that is perpendicular to Line #1]\r
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