document.write( "Question 491313: Gloria invested 60,000 pesos for 1 year, part at 9% and part at 4 1/2% simple interest. if the accounts earn 3,438.75 total interest, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #334591 by mananth(16946)\"\" \"About 
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Investment I 9.00% per annum ---x
\n" ); document.write( "Investment II 4.50% per annum ---y
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\n" ); document.write( "x + y= 60000 ------------------------1
\n" ); document.write( "9.00% x + 4.50% y = $3,438.75
\n" ); document.write( "Multiply by 100
\n" ); document.write( "9 x + 4.5 y = $343,875.00
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\n" ); document.write( "Multiply (1) by -9
\n" ); document.write( "we get
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\n" ); document.write( "-9 x -9 y = -540000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "0 x -4.5 y = -$196,125.00
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\n" ); document.write( "divide by -4.5
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\n" ); document.write( " y = $43,583.33
\n" ); document.write( "Balance $16,416.67
\n" ); document.write( "CHECK
\n" ); document.write( "$16,416.67 $1,477.50
\n" ); document.write( "$43,583.33 $1,961.25
\n" ); document.write( "Total $3,438.75
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