document.write( "Question 491328: The area of a rectangle is represented by x2-4, and a pair of consecutive sides are measured x+4 and x-3. What is the area of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #334586 by nerdybill(7384)\"\" \"About 
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The area of a rectangle is represented by x^2-4, and a pair of consecutive sides are measured x+4 and x-3. What is the area of the rectangle?
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\n" ); document.write( "Solve for x:
\n" ); document.write( "(x+4)(x-3) = x^2-4
\n" ); document.write( "FOIL left side:
\n" ); document.write( "x^2-3x+4x-12 = x^2-4
\n" ); document.write( "x^2+x-12 = x^2-4
\n" ); document.write( "x-12 = -4
\n" ); document.write( "x = 8
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\n" ); document.write( "Area was given as:
\n" ); document.write( "x^2-4
\n" ); document.write( "plug in our value of x:
\n" ); document.write( "8^2-4
\n" ); document.write( "64-4
\n" ); document.write( "60 square units (answer)\r
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