document.write( "Question 491223: A jet is flying from Hawaii to San Fransisco a distance of 2400 miles. In still air the jet flies at 600mph but there is now a 40mph tailwind. In case of emergency how many hours after takeoff will it be faster for the jet to go on to San Francisco rather than return to Hawaii? \n" ); document.write( "
Algebra.Com's Answer #334574 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
A jet is flying from Hawaii to San Fransisco a distance of 2400 miles. In still air the jet flies at 600mph but there is now a 40mph tailwind. In case of emergency how many hours after takeoff will it be faster for the jet to go on to San Francisco rather than return to Hawaii?
\n" ); document.write( "**
\n" ); document.write( "let x=distance covered on the way to SF at turn-around point
\n" ); document.write( "2400-x=Remaining distance to SF at turn-around point
\n" ); document.write( "Speed of plane with tailwind=600+40=640mph (go on to SF)
\n" ); document.write( "Speed of plane against wind=600-40=560mph (rtn to Hawaii)
\n" ); document.write( "Travel time=distance/speed
\n" ); document.write( "Time to go on to SF =Time to return to Hawaii
\n" ); document.write( "(2400-x)/640=x/560
\n" ); document.write( "640x=560*2400-560x
\n" ); document.write( "1200x=560*2400
\n" ); document.write( "x=560*2400/1200=1120 miles
\n" ); document.write( "Travel time=(2400-1120)640=2hrs
\n" ); document.write( "ans:
\n" ); document.write( "After two hours after takeoff it will be faster for the jet to go on to San Francisco rather than return to Hawaii \n" ); document.write( "
\n" );