document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483319>Question 483319</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3/2log 9/25 - 5log 2/3 + 2log 2/8, all in base 10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334563 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/2log 9/25 - 5log 2/3 + 2log 2/8, all in base 10<BR>\n" );
document.write( "**<BR>\n" );
document.write( "3/2log 9/25 - 5log 2/3 + 2log 2/8<BR>\n" );
document.write( "place under a single log<BR>\n" );
document.write( "log[(9/25)^(3/2)*(2/8)^2/(2/3)^5]<BR>\n" );
document.write( "log[(27/125)*(1/16)/(32/243)]<BR>\n" );
document.write( "log[.1025]=-0.9893 </SPAN>\n" );
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