document.write( "Question 491211: Solve by completing the square...
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document.write( "1. x^2-6x+8=0
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document.write( "2. x^2+5x+6=0 \n" );
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Algebra.Com's Answer #334560 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! x^2-6x+8=0 \n" ); document.write( "x^2-6x=-8 \n" ); document.write( "Half of the middle term coefficient (6) is 3 so add square of 3 both sides of the equation. \n" ); document.write( "x^2-6x+9=-8+9 \n" ); document.write( "x^-2(3)x+(3)^2=1 \n" ); document.write( "x^-2(3)x+(3)^2=1 \n" ); document.write( "(x-3)^2=1 \n" ); document.write( "x-3=1 or x-3=-1 \n" ); document.write( "x=1+3 or x=-1+3 \n" ); document.write( "x=4 or x=2 \n" ); document.write( " \n" ); document.write( "x^2+5x+6=0 \n" ); document.write( "x^2+5x=-6 \n" ); document.write( "Half of the middle term coefficient (5) is 5/2 so add square of 5/2 both sides of the equation. \n" ); document.write( "x^2+5x+25/4=-6+25/4 \n" ); document.write( "x^2+2 (5/2)x+25/4=-6+25/4 \n" ); document.write( "x^2+2 (5/2)x+25/4=(-24+25)/4 \n" ); document.write( "x^2+2 (5/2)x+25/4=1/4 \n" ); document.write( "(x+5/2)^2=1/4 \n" ); document.write( "x+5/2=1/2 or x+5/2=-1/2 \n" ); document.write( "x=1/2-5/2 or x=-1/2-5/2 \n" ); document.write( "x=(1-5)/2 or x=(-1-5)/2 \n" ); document.write( "x=-4/2 or x=-6/2 \n" ); document.write( "x=-2 or x=-3 \n" ); document.write( " \n" ); document.write( " |