document.write( "Question 491107: suppose you invest $15,000 in two funds paying 11 1/2% and 14% simple interest. the total annual interest is $1950. how much is invested in each fund? \n" ); document.write( "
Algebra.Com's Answer #334526 by mananth(16946)\"\" \"About 
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Investment I 11.50% per annum ---x
\n" ); document.write( "Investment II 14.00% per annum ---y
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\n" ); document.write( "x + y= 15000 ------------------------1
\n" ); document.write( "11.50% x + 14.00% y = $1,950.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "11.5 x + 14 y = $195,000.00 --------2
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\n" ); document.write( "Multiply (1) by -11.5
\n" ); document.write( "we get
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\n" ); document.write( "-11.5 x -11.5 y = -172500.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "0 x+ 2.5 y = $22,500.00
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\n" ); document.write( "divide by 2.5
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\n" ); document.write( " y = $9,000.00 investment at 14.00%
\n" ); document.write( "Balance $6,000.00 investment at 11.50%\r
\n" ); document.write( "\n" ); document.write( "CHECK
\n" ); document.write( "$6,000.00 $690.00
\n" ); document.write( "$9,000.00 $1,260.00
\n" ); document.write( "Total $1,950.00
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