document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=491185>Question 491185</A>: <I><SPAN STYLE=\"word-break: break-all;\"> E is the midpoint of segment DF, DE= 2x + 4, and EF= 3x - 1. Find DE, EF and DF. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334520 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since E is the midpoint of DF, then DE = EF, so...<BR>\n" );
document.write( "2x+4 = 3x-1 Subtract 2x from both sides.<BR>\n" );
document.write( "4 = x-1 Add 1 to both sides.<BR>\n" );
document.write( "x = 5<BR>\n" );
document.write( "DE = 2x+4 Substitute x = 5.<BR>\n" );
document.write( "DE = 2(5)+4<BR>\n" );
document.write( "DE = 14<BR>\n" );
document.write( "EF = 3x-1 Substitute x = 5.<BR>\n" );
document.write( "EF = 3(5)-1<BR>\n" );
document.write( "EF = 14<BR>\n" );
document.write( "DF = 14+14<BR>\n" );
document.write( "DF = 28.  </SPAN>\n" );
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