document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=50375>Question 50375</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sume of this series.<BR>\n" );
document.write( "28+35+42+49+......728.<BR>\n" );
document.write( "I know this is 7 added each time.  But stuck on the equation to figure.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33452 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33452\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 28+35+42+49+......728.\r<BR>\n" );
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document.write( "The sum is the average of the 1st and last terms times the number of terms.\r<BR>\n" );
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document.write( "S=(1/2)n(1st + last)<BR>\n" );
document.write( "Need to find number of terms, as follows:<BR>\n" );
document.write( "728-28=700<BR>\n" );
document.write( "700/7 = 100<BR>\n" );
document.write( "So, 728 is the 100th term.\r<BR>\n" );
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document.write( "S=1/2(100)(28+728)<BR>\n" );
document.write( "S=50(756)<BR>\n" );
document.write( "S=37,800\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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