document.write( "Question 491146: 3r-2s=5 and 2r+3s=12 \n" ); document.write( "
Algebra.Com's Answer #334501 by mananth(16946)\"\" \"About 
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3 r -2 s = 5 .............1
\n" ); document.write( "2 r + 3 s = 12 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by 3
\n" ); document.write( "Multiply (2) by 2
\n" ); document.write( "9 r -6 s = 15
\n" ); document.write( "4 r 6 s = 24
\n" ); document.write( "Add the two equations
\n" ); document.write( "13 r = 39
\n" ); document.write( "/ 13
\n" ); document.write( "r = 3
\n" ); document.write( "plug value of r in (1)
\n" ); document.write( "3 r + -2 s = 5
\n" ); document.write( "9 + -2 s = 5
\n" ); document.write( " -2 s = 5 -9
\n" ); document.write( " -2 s = -4
\n" ); document.write( " s = 2
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