document.write( "Question 491146: 3r-2s=5 and 2r+3s=12 \n" ); document.write( "
Algebra.Com's Answer #334501 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 3 r -2 s = 5 .............1 \n" ); document.write( "2 r + 3 s = 12 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by 3 \n" ); document.write( "Multiply (2) by 2 \n" ); document.write( "9 r -6 s = 15 \n" ); document.write( "4 r 6 s = 24 \n" ); document.write( "Add the two equations \n" ); document.write( "13 r = 39 \n" ); document.write( "/ 13 \n" ); document.write( "r = 3 \n" ); document.write( "plug value of r in (1) \n" ); document.write( "3 r + -2 s = 5 \n" ); document.write( "9 + -2 s = 5 \n" ); document.write( " -2 s = 5 -9 \n" ); document.write( " -2 s = -4 \n" ); document.write( " s = 2 \n" ); document.write( " \n" ); document.write( " |