document.write( "Question 50343This question is from textbook
\n" ); document.write( ": I am trying to identify the axis of symmetry and creating an x and y table for the graph. My numbers are wrong because it doesn't resemble a parabola... y=x^2-5x+3 and y=-x^2+6x-2. I am kinda stuck if you can assit please. \n" ); document.write( "
Algebra.Com's Answer #33447 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
y=x^2-5x+3
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\n" ); document.write( "Complete the square to put into vertex form, as follows:
\n" ); document.write( "x^2-5x+(5/2)^2=y-3+(5/2)^2
\n" ); document.write( "(x-(5/2))^2 = y-12/4+25/4
\n" ); document.write( "(x-(5/2))^2 = y+ 13/4
\n" ); document.write( "The vertex is (5/2,-13/4)
\n" ); document.write( "The axis of symmetry is x=5/2
\n" ); document.write( "You can create a x,y table for the graph by substituting
\n" ); document.write( "values for x in the original equation and solving for y.
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\n" ); document.write( "\n" ); document.write( "and y=-x^2+6x-2
\n" ); document.write( "--------
\n" ); document.write( "-(x^2-6x+3^2)=y+2-3^2
\n" ); document.write( "-(x-3)^2=y-7
\n" ); document.write( "Axis of symmetry is x=3\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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