document.write( "Question 490996: 2x^-x=1 \n" ); document.write( "
Algebra.Com's Answer #334415 by ccs2011(207)![]() ![]() You can put this solution on YOUR website! Make exponents positive \n" ); document.write( "--> \n" ); document.write( "--> \n" ); document.write( "------------------------- \n" ); document.write( "This cannot be solved explicitly using elementary operations \n" ); document.write( "see wolfram alpha more explanation \n" ); document.write( "http://www.wolframalpha.com/input/?i=x^x+%3D+2 \n" ); document.write( "--------------------------------- \n" ); document.write( "You can graph y = x^x, and see where y =2. \n" ); document.write( "If you know calculus you can use Newtons method to approximate the root of f(x) = x^x - 2 \n" ); document.write( "Approximate solution is x = 1.5596 \n" ); document.write( " |