document.write( "Question 490996: 2x^-x=1 \n" ); document.write( "
Algebra.Com's Answer #334415 by ccs2011(207)\"\" \"About 
You can put this solution on YOUR website!
Make exponents positive
\n" ); document.write( "--> \"2%2F%28x%5Ex%29+=+1\"
\n" ); document.write( "--> \"x%5Ex+=+2\"
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\n" ); document.write( "This cannot be solved explicitly using elementary operations
\n" ); document.write( "see wolfram alpha more explanation
\n" ); document.write( "http://www.wolframalpha.com/input/?i=x^x+%3D+2
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\n" ); document.write( "You can graph y = x^x, and see where y =2.
\n" ); document.write( "If you know calculus you can use Newtons method to approximate the root of f(x) = x^x - 2
\n" ); document.write( "Approximate solution is x = 1.5596
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