document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=490923>Question 490923</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measures of two angles are in the ratio 4:5. the larger of the two angles is 60 less than twice the smaller angle. find the measure of each angle. complementary or supplementary? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334365 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334365\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We will let x be the larger angle and y be the smaller angle.<BR>\n" );
document.write( "angle y = 4/5x<BR>\n" );
document.write( "Now, set up two equations<BR>\n" );
document.write( "4x = 5y<BR>\n" );
document.write( "x + 60 = 2y<BR>\n" );
document.write( "4x - 5y = 0<BR>\n" );
document.write( "x  -2y = -60<BR>\n" );
document.write( "-4x +8y = 240 Multiply the second equation by -4 and subtract from the first equation.<BR>\n" );
document.write( "3y = 240<BR>\n" );
document.write( "y = 80 degrees, which is 4/5 of x.<BR>\n" );
document.write( " x = 100 degrees.<BR>\n" );
document.write( "As a check, 2(80) - 60 = 100. This does check.<BR>\n" );
document.write( "Cleomenius.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );