document.write( "Question 490857: a stone is thrown straight upward with a speed of 20m/s,it is caught on its way down at a point 5.0m above where it was thrown,how far was it going when it was caught,and how long did the trip take \n" ); document.write( "
Algebra.Com's Answer #334341 by ccs2011(207) You can put this solution on YOUR website! Initial velocity = 20 \n" ); document.write( "h(t) = -4.9t^2 +20t \n" ); document.write( "Solve for t when h(t) = 5 \n" ); document.write( "--> \n" ); document.write( "--> \n" ); document.write( "----------------------------------- \n" ); document.write( "Use quadratic formula \n" ); document.write( " \n" ); document.write( "--------------------------------- \n" ); document.write( "--> \n" ); document.write( "--> \n" ); document.write( "--> \n" ); document.write( "We want the time when the stone is on its way down which will be the longer time \n" ); document.write( "--> \n" ); document.write( "Trip took 3.814 sec \n" ); document.write( "------------------------------------- \n" ); document.write( "v(t) = -9.8t + 20 \n" ); document.write( "Solve for when t = 3.814 \n" ); document.write( "--> \n" ); document.write( "Speed is always positive \n" ); document.write( "Stone was traveling at 17.378 m/s when caught \n" ); document.write( " |