document.write( "Question 490788: the tens digit of a two number is three greater than the ones digit. the difference between twice the original number and half the number obtained after reversing the digits is 108 \n" ); document.write( "

Algebra.Com's Answer #334316 by stanbon(75887) $\"\"$ $\"About$

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the tens digit of a two number is three greater than the ones digit. the difference between twice the original number and half the number obtained after reversing the digits is 108
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\n" ); document.write( "Let the number be 10t+u
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\n" ); document.write( "Equations:
\n" ); document.write( "t = u + 3
\n" ); document.write( "2(10t+u)-(1/2)(10u+t) = 108
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\n" ); document.write( "Modify:
\n" ); document.write( "t = u+3
\n" ); document.write( "4(10t+u) - (10u+t) = 216
\n" ); document.write( "----
\n" ); document.write( "39t - 6u = 216
\n" ); document.write( "t = u+3
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\n" ); document.write( "Substitute and solve for \"u\":
\n" ); document.write( "39(u+3) - 6u = 216
\n" ); document.write( "33u = 216-3*39
\n" ); document.write( "33u = 99
\n" ); document.write( "u = 3
\n" ); document.write( "---
\n" ); document.write( "Solve for \"t\":
\n" ); document.write( "t = u + 3
\n" ); document.write( "t = 6
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\n" ); document.write( "The number is 63
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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