document.write( "Question 50337: Two angles are complementary. The measure of one angle is 21more than twice the measure of the other angle. Find the measures of the angles.\r
\n" ); document.write( "\n" ); document.write( "I am a parent trying to help a sophmore with this question. I just wanted to see if I was on the right track. Thanks for any help you could give.
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Algebra.Com's Answer #33426 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
There are (at leastl!) TWO ways to set up this equation. I think the easier way is to:\r
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\n" ); document.write( "\n" ); document.write( "Let x= one of the angles
\n" ); document.write( "2x+21 = the other angle\r
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\n" ); document.write( "\n" ); document.write( "The equation is
\n" ); document.write( "x + 2x +21 = 90
\n" ); document.write( "3x +21=90
\n" ); document.write( "3x = 69
\n" ); document.write( "x=23 degrees
\n" ); document.write( "2x+21 = 46+21 = 67 degrees\r
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\n" ); document.write( "\n" ); document.write( "Check: 23 +67 = 90\r
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\n" ); document.write( "\n" ); document.write( "The other way is to
\n" ); document.write( "Let x = the first angle
\n" ); document.write( "90-x = the second angle\r
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\n" ); document.write( "\n" ); document.write( "The equation is from this sentence, where of course \"IS\" means \"=\":
\n" ); document.write( "The second angle IS 21 more than twice the first angle.
\n" ); document.write( "90-x= 2x+21\r
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\n" ); document.write( "\n" ); document.write( "It comes out the same.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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