document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=488553>Question 488553</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use the pythagorean theorem to find the distance between each pair of points.<BR>\n" );
document.write( "C(-10, 12), D (-7, 6) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334256 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334256\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You would plot these rwo points, as well as plot a third point (-10, 6), named E. to form a right triangle.<BR>\n" );
document.write( "(CE)^2 + (DE)^2 = (CD)^2<BR>\n" );
document.write( "(6)^2 + (-3)^2 = (CD)^2<BR>\n" );
document.write( "36 + 9  = (CD)^2<BR>\n" );
document.write( "45 = (CD)^2<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2845%29 ALIGN=MIDDLE  ALT=\"sqrt%2845%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = CD<BR>\n" );
document.write( "3<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%285%29 ALIGN=MIDDLE  ALT=\"sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = CD<BR>\n" );
document.write( "Cleomenius\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );