document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=490707>Question 490707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If p is directly proportional to q, and p=18 when q=3, find q when p is 48 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334220 by </B><A HREF=/tutors/aboutme.mpl?userid=John10><B>John10(297)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=John10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=John10><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> because p is directly proportions to q then the formula is:<BR>\n" );
document.write( "p = k * q where k is the variance constant<BR>\n" );
document.write( "If  p = 18 and q = 3 then<BR>\n" );
document.write( "k = p/q = 18/3 = 6<BR>\n" );
document.write( "Then we find the new q:<BR>\n" );
document.write( "p = 6 * q then q = p/6 = 48/6 = 8<BR>\n" );
document.write( "John10:) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );