document.write( "Question 490706: Hey,\r
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document.write( "If you could help me remember how to do this type of problem it would be AWESOME!\r
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document.write( "Form a polynomial degree with real coefficients so that 2+i and -1 are zeros.\r
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document.write( "Thanks!\r
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document.write( "(Answer is x^3-3x^2+x+5; just need to know how to figure this out - thanks! \n" );
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Algebra.Com's Answer #334218 by John10(297)![]() ![]() You can put this solution on YOUR website! We know this polynomial has at least 3 solutions which are (2 + i), (2 - i) and -1 \n" ); document.write( "Thus we apply the formula (x - a)(x - b)(x - c)= 0 where a,b, and c are given solutions. \n" ); document.write( "(x - 2 - i)(x - 2 + i)(x + 1) = 0 \n" ); document.write( "Use the distributive to multiply from left to right \n" ); document.write( "(x^2 - 2x + xi - 2x +4 - 2i - xi + 2i - i^2)(x + 1) = 0 \n" ); document.write( "Simplify \n" ); document.write( "(x^2 - 4x + 5)(x + 1) = 0 \n" ); document.write( "x^3 + x^2 - 4x^2 - 4x + 5x + 5 = 0 \n" ); document.write( "x^3 - 3x^2 + x + 5 = 0 \n" ); document.write( "The LEFT SIDE is what you are looking for. \n" ); document.write( "John10:) \n" ); document.write( " |