document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=490397>Question 490397</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if i have a triangle with sides 40cm, 32cm, and 15.3cm and an angle of 112 degrees where the 32cm side and 15.3cm side meet, what is the measure of the angle opposite of the side that is 15.3cm? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334192 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can use the law of sines\r<BR>\n" );
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document.write( "40/sin112 = 15.3 /x<BR>\n" );
document.write( "x = sin 20.77, the angle opposite the 15.3 cm side.<BR>\n" );
document.write( "For a check, using the law of sines the angle opposite the 32 cm side = 47.88.<BR>\n" );
document.write( "47.88 degrees + 20.77 degrees + 112 degrees = 180.65, approx 180.<BR>\n" );
document.write( "Cleomenius.<BR>\n" );
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