document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=490537>Question 490537</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one of the supplementary angle exeeds the other by 15 degree.find the measure of the supplementary angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334129 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334129\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  one of the supplementary angle exeeds the other by 15 degree.find the measure of the supplementary angle<BR>\n" );
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document.write( "Angle: x<BR>\n" );
document.write( "Supplement: 180-x<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "180-x = x + 15<BR>\n" );
document.write( "2x = 165<BR>\n" );
document.write( "x = 82.5 (the angle)<BR>\n" );
document.write( "180-82.5 = 97.5 degrees (supplement)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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